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A punter on Westview High School's football team kicks a ball straight up from 5 feet above the ground with an initial upward velocity of 45 feet per second. The height of the ball above ground after t seconds is given by the equation h = –16t2 + 45t + 5, where h is the height of the ball in feet and t is the time in seconds since the punt. What is the maximum height of the ball, to the nearest foot?
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"maximum height" is the vertex so you will calculate x = (-b/2a) and then plug that back into the equation to find the maximum height remember that a quadratic equation has the general form ax^2 + bx + c
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