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Mathematics 8 Online
princeevee:

i need help with some questions

princeevee:

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princeevee:

@Vocaloid

Vocaloid:

line KI bisects angle I so if <GIK is 28 then what is angle I?

princeevee:

i got it, thanks

princeevee:

actually, i got it wrong..

Vocaloid:

hm? so since GIK is one half the entire angle I, then angle I = 28*2 = 56 so GEI = 180 - 56 - 98 = 26 if I"m not mistaken

princeevee:

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Vocaloid:

good

princeevee:

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Vocaloid:

good attempt but not quite since this is a circumcenter all the dotted lines are equal

princeevee:

so D?

Vocaloid:

3.6 is not the length of the dotted lines

princeevee:

i meant to say C

Vocaloid:

good, C

princeevee:

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Vocaloid:

|dw:1529115896991:dw| be careful, angle bisectors would be incenter not circumcenter

princeevee:

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Vocaloid:

perfect

princeevee:

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Vocaloid:

hm, not quite, make sure you are picking two angles that are adjacent to each other, and split in the middle with a bisector

princeevee:

ah, so D?

Vocaloid:

good

princeevee:

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Vocaloid:

good

princeevee:

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Vocaloid:

good

princeevee:

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Vocaloid:

|dw:1529116823495:dw| keep in mind the circumcenter can be outside if the triangle is obtuse (see the upper right corner)

princeevee:

so false

Vocaloid:

yup that's correct

princeevee:

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princeevee:

LN

Vocaloid:

good

princeevee:

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Vocaloid:

huh i'm not 100% sure how to prove it but I have a suspicion that <1 is one half of <MNO so 2(3x+5) = 7x - 7 solve for x

princeevee:

17

Vocaloid:

good i'm just going to see if I can get someone to verify that for me

princeevee:

ok

princeevee:

...

Vocaloid:

yeah the left side and right side are congruent because of the HL theorem so yes, x = 17

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