Mathematics
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princeevee:
i need help with some questions
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princeevee:
princeevee:
@Vocaloid
Vocaloid:
line KI bisects angle I
so if <GIK is 28 then what is angle I?
princeevee:
i got it, thanks
princeevee:
actually, i got it wrong..
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Vocaloid:
hm?
so since GIK is one half the entire angle I, then angle I = 28*2 = 56
so GEI = 180 - 56 - 98 = 26 if I"m not mistaken
princeevee:
Vocaloid:
good
princeevee:
Vocaloid:
good attempt but not quite
since this is a circumcenter all the dotted lines are equal
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princeevee:
so D?
Vocaloid:
3.6 is not the length of the dotted lines
princeevee:
i meant to say C
Vocaloid:
good, C
princeevee:
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Vocaloid:
|dw:1529115896991:dw|
be careful, angle bisectors would be incenter not circumcenter
princeevee:
Vocaloid:
perfect
princeevee:
Vocaloid:
hm, not quite, make sure you are picking two angles that are adjacent to each other, and split in the middle with a bisector
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princeevee:
ah, so D?
Vocaloid:
good
princeevee:
Vocaloid:
good
princeevee:
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Vocaloid:
good
princeevee:
Vocaloid:
|dw:1529116823495:dw|
keep in mind the circumcenter can be outside if the triangle is obtuse (see the upper right corner)
princeevee:
so false
Vocaloid:
yup that's correct
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princeevee:
princeevee:
LN
Vocaloid:
good
princeevee:
Vocaloid:
huh
i'm not 100% sure how to prove it but I have a suspicion that <1 is one half of <MNO
so 2(3x+5) = 7x - 7 solve for x
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princeevee:
17
Vocaloid:
good
i'm just going to see if I can get someone to verify that for me
princeevee:
ok
princeevee:
...
Vocaloid:
yeah the left side and right side are congruent because of the HL theorem so yes, x = 17