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Mathematics 27 Online
princeevee:

i need some answers checked

princeevee:

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princeevee:

@Vocaloid

Vocaloid:

the two triangles are similar so its possible to determine a value KM/MN = LK/NO plug in the sides and find MN

princeevee:

7.5?

Vocaloid:

good

princeevee:

says it's wrong.

Vocaloid:

huh, really? that's strange

princeevee:

yeah...

Vocaloid:

I guess we can't assume that they're proportional then making your original solution correct

princeevee:

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Vocaloid:

good

princeevee:

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Vocaloid:

hm I'm pretty sure its not transitive notice how the two triangles share the top angle the two sides on the left and right are also similar giving us SAS theorem

princeevee:

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Vocaloid:

good

princeevee:

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princeevee:

?

princeevee:

@Vocaloid hello?

Vocaloid:

hm not quite using proportional sides (x-3)/9 = (x+2)/12

princeevee:

i got 0..

Vocaloid:

cross multiply 12(x-3) = 9(x+2) distribute then solve for x

princeevee:

18?

Vocaloid:

good

princeevee:

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Vocaloid:

symmetric not reflexive reflexive is stating something is equal to itself

princeevee:

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Vocaloid:

good

princeevee:

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Vocaloid:

I think it's true (not sure how picky they are w/ the order of the naming)

princeevee:

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Vocaloid:

good

princeevee:

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Vocaloid:

again I'm not sure how picky they are with the naming convention but since they're naming the same two triangles each time I'm thinking it's actually true

princeevee:

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Vocaloid:

good

princeevee:

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Vocaloid:

another case where two triangles share one angle and a pair of corresponding sides, so SAS

princeevee:

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princeevee:

i'm jumping through both symmetric and transitive

Vocaloid:

it's transitive

princeevee:

ok

princeevee:

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Vocaloid:

"side side side" similarity shouldn't require any angles

princeevee:

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Vocaloid:

hm not quite FV/VI = GV/VH solve for VI

princeevee:

2.00?

Vocaloid:

5.84/x = 6.55/3.27 cross multiplying gives us 6.55x = 5.84*3.27 x = ?

princeevee:

5?

Vocaloid:

6.55x = 5.84*3.27 multiply what 5.84 * 3.27 is then divide by 6.55 to isolate x

princeevee:

2.9

Vocaloid:

good so 2.9 = your sol'n

princeevee:

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Vocaloid:

good

princeevee:

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princeevee:

i think i've did this one before...

Vocaloid:

yeah this is not transitive (transitive: a = b, b = c, a = c) this has to be SAS because the two triangles share an angle and the proportional sides on the left + right

princeevee:

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Vocaloid:

good

princeevee:

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Vocaloid:

good guess but if we know that all the first triangle's sides are equal (let's say each side = a) and all the second's triangle's sides are equal (let's say each side = b) then all the corresponding side ratios are b/a making the triangle similar via SSS

Vocaloid:

in general all equilateral triangles are similar according to this logic

princeevee:

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jhonyy9:

@princeevee try understanding these above wrote by @Vocaloid so this choice marked by you not is right ok. ?

princeevee:

i got that my answer was incorrect..

jhonyy9:

yes - ok

Vocaloid:

hm? why wouldn't the second choice be correct? it looks ok to me

jhonyy9:

sorry we talk about past exercise @Vocaloid

jhonyy9:

for the last posted exercise the second choice is right sure

jhonyy9:

using the proportionality of coresponding sides

princeevee:

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Vocaloid:

good

princeevee:

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princeevee:

actually, wait, this might be true.

princeevee:

actually no, it's false

princeevee:

you also need a compass

Vocaloid:

yup, false

princeevee:

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Vocaloid:

good

princeevee:

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Vocaloid:

"corresponding position" so <1 and <2 need to be oriented in the same direction/position

Vocaloid:

|dw:1529866692856:dw|

princeevee:

oh, alright

princeevee:

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Vocaloid:

good

princeevee:

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Vocaloid:

hm, not quite the steps are slightly different https://mathbitsnotebook.com/Geometry/Constructions/CCconstruction4.html

princeevee:

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Vocaloid:

|dw:1529867132241:dw| this one is actually true, if blue and orange are both perpendicular to black, then blue and orange have to be parallel to each other

princeevee:

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Vocaloid:

good

princeevee:

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Vocaloid:

good

princeevee:

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Vocaloid:

hm, this one is true, if you fold the paper so that A matches with B, you will create a crease down the middle of the paper that splits the segment in 2

princeevee:

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Vocaloid:

good

princeevee:

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Vocaloid:

not quite m<1 is not equal to 4x; it's supplementary so 4x + 76 = 180 solve for x

princeevee:

oh, 26

Vocaloid:

good

princeevee:

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Vocaloid:

|dw:1529868274081:dw| using our previous problem as a reference, consecutive interior angles are not congruent, they are suppelementary

princeevee:

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Vocaloid:

good

princeevee:

1 attachment
Vocaloid:

good

princeevee:

1 attachment
Vocaloid:

good

princeevee:

1 attachment
Vocaloid:

good

princeevee:

1 attachment
Vocaloid:

|dw:1529869141953:dw| alternate exterior angles are congruent not complementary

princeevee:

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Vocaloid:

good

princeevee:

1 attachment
Vocaloid:

good

princeevee:

1 attachment
Vocaloid:

good

princeevee:

1 attachment
Vocaloid:

good

princeevee:

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Vocaloid:

good

princeevee:

they just...

princeevee:

they just made the same question twice..

princeevee:

i'm going to close this to prevent lag

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