Question

Celina measured the height of a window frame as 5.55 feet, but the actual height was 6 feet. What is the percentage of error in Celina's measurement?

Answer 1

percent error = 100*(measured height - actual height)/(actual height)

Answer 2

so 7.50%

Answer 3

-7.50% would be better if there's a way to enter a negative number

if not, then try 7.50%

Answer 4

ok