Question

What are the excluded values? x+3/y(z+5)
x = -3; z = 0
y = -5; z = 0
y = 0; z = -5
none of the above

Answer 1

your denominator is y*(z+5) right?

so your denominator cannot equal 0

y = 0 and
(z+5) = 0 will give you your excluded values


solve for z

Answer 2

So z=0?

Answer 3

if z + 5 = 0

what does z = ?

Answer 4

Oh... It will be... -5
Right?

Answer 5

good so

y = 0; z = -5 = your sol'n

Answer 6

Thank you!