Data Management: A jury of 12 people is to be chosen randomly from a list containing 10 men and 12 women. What is the probability that there is a least one man on the jury?
would be easier to find the probability of getting no men on the jury, then taking 1 - that probability so getting all women, we have 12 women out of a possible 22 people so P(only women) = (12/22)(11/21)(10/20)(9/19)(8/18)(7/17)(6/16)(5/15)(4/14)(3/13)(2/12)(1/11) then P(at least one man) = 1 - P(only women)
so i would divide all those in the brackets then times them to find my answer?
Limited statistics memory, but I believe you multiply first before dividing...?
yeah it's just a series of fractions so you'd multiply across all the numerators to get 12 factorial, then 22 * 21 * 20... *11 for the denominator, then divide first quantity/second quantity
i'm sure there's an easier way to express this w/ factorial notation, it's just slipping my mind at the moment
oh ok thanks guys ill try it out and see if get it!!
for large calculations I would just chuck it into wolframalpha.com and let it simplify the fraction
or symbolab.com
oh ok, never heard of these sites thanks ill use them rn to make it easier, again thanks guys!!<3
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hey uh for the part when you said "yeah it's just a series of fractions so you'd multiply across all the numerators to get 12 factorial, then 22 * 21 * 20... *11 for the denominator, then divide first quantity/second quantity" i understand the numerator part but can you explain the denominator part a bit more?
like, if you have (A/B) * (C/D) you'd multiply the numerators (A*C) and then the denominators (B*D), then the final result is (A*C)/(B*D) same logic with (12/22)(11/21)(10/20)(9/19)(8/18)(7/17)(6/16)(5/15)(4/14)(3/13)(2/12)(1/11) for the numerators multiply 12 * 11 * 10... etc. for the denominators multiply 22 * 21 * 20 * 19 * 18... * 11
i got 3.0974447e+14 idek what the e is lol please help
that seems like \[3.0974447\times10^{-14}\]
e is an exponent setting my calculator in fraction mode gives me 646645/646646 as the sol'n
You can use "e(numerical value)" instead of "\(10^{\text{numerical value}}\)"
Sorry, that should be \(10^{14}\) not negative 14. My bad
so when it comes down to what the fraction should be would it be " 12!/3.0974447e14 " ??
product is written as 1 - (12/22)(11/21)(10/20)(9/19)(8/18)(7/17)(6/16)(5/15)(4/14)(3/13)(2/12)(1/11) which can be written as 1 - (12!)/(22*21*20*19*18*17*16*15*14*13*12*11) which simplifies into 646645/646646
so 1-1? 0 is the answer?
@Vocaloid
"1 - (12!)/(22*21*20*19*18*17*16*15*14*13*12*11) which simplifies into 646645/646646" indicating that 646645/646646 is the solution.
sorry i keep asking repetitive questions but i know you said that is the solution but i gotta find the probabilty as in a percentage or fraction so when i divided those two numbers i got 99%.. is that what my answer should be or am i way off?
"percentage or fraction" seems to imply that 646645/646646 would be an acceptable solution however, if you must report the solution as a percentage, then yes, 99% would be an acceptable solution do they specify how many digits to round to?
no they dont the question i posted above which was "A jury of 12 people is to be chosen randomly from a list containing 10 men and 12 women. What is the probability that there is a least one man on the jury?" was all they asked
hm. 646645/646646 is more accurate, 99% could work too
alright thanks so much for the help i really appreciate it!!
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