Data Management: A jury of 12 people is to be chosen randomly from a list containing 10 men and 12 women. What is the probability that there is a least one man on the jury?

9 months agowould be easier to find the probability of getting no men on the jury, then taking 1 - that probability so getting all women, we have 12 women out of a possible 22 people so P(only women) = (12/22)(11/21)(10/20)(9/19)(8/18)(7/17)(6/16)(5/15)(4/14)(3/13)(2/12)(1/11) then P(at least one man) = 1 - P(only women)

9 months agoso i would divide all those in the brackets then times them to find my answer?

9 months agoLimited statistics memory, but I believe you multiply first before dividing...?

9 months agoyeah it's just a series of fractions so you'd multiply across all the numerators to get 12 factorial, then 22 * 21 * 20... *11 for the denominator, then divide first quantity/second quantity

9 months agoi'm sure there's an easier way to express this w/ factorial notation, it's just slipping my mind at the moment

9 months agooh ok thanks guys ill try it out and see if get it!!

9 months agofor large calculations I would just chuck it into wolframalpha.com and let it simplify the fraction

9 months agooh ok, never heard of these sites thanks ill use them rn to make it easier, again thanks guys!!<3

9 months ago♥

9 months agohey uh for the part when you said "yeah it's just a series of fractions so you'd multiply across all the numerators to get 12 factorial, then 22 * 21 * 20... *11 for the denominator, then divide first quantity/second quantity" i understand the numerator part but can you explain the denominator part a bit more?

9 months agolike, if you have (A/B) * (C/D) you'd multiply the numerators (A*C) and then the denominators (B*D), then the final result is (A*C)/(B*D) same logic with (12/22)(11/21)(10/20)(9/19)(8/18)(7/17)(6/16)(5/15)(4/14)(3/13)(2/12)(1/11) for the numerators multiply 12 * 11 * 10... etc. for the denominators multiply 22 * 21 * 20 * 19 * 18... * 11

9 months agoi got 3.0974447e+14 idek what the e is lol please help

9 months agothat seems like \[3.0974447\times10^{-14}\]

9 months agoe is an exponent setting my calculator in fraction mode gives me 646645/646646 as the sol'n

9 months agoYou can use "e(numerical value)" instead of "\(10^{\text{numerical value}}\)"

9 months agoSorry, that should be \(10^{14}\) not negative 14. My bad

9 months agoso when it comes down to what the fraction should be would it be " 12!/3.0974447e14 " ??

9 months agoproduct is written as 1 - (12/22)(11/21)(10/20)(9/19)(8/18)(7/17)(6/16)(5/15)(4/14)(3/13)(2/12)(1/11) which can be written as 1 - (12!)/(22*21*20*19*18*17*16*15*14*13*12*11) which simplifies into 646645/646646

9 months agoso 1-1? 0 is the answer?

9 months ago@Vocaloid

9 months ago"1 - (12!)/(22*21*20*19*18*17*16*15*14*13*12*11) which simplifies into 646645/646646" indicating that 646645/646646 is the solution.

9 months agosorry i keep asking repetitive questions but i know you said that is the solution but i gotta find the probabilty as in a percentage or fraction so when i divided those two numbers i got 99%.. is that what my answer should be or am i way off?

9 months ago"percentage or fraction" seems to imply that 646645/646646 would be an acceptable solution however, if you must report the solution as a percentage, then yes, 99% would be an acceptable solution do they specify how many digits to round to?

9 months agono they dont the question i posted above which was "A jury of 12 people is to be chosen randomly from a list containing 10 men and 12 women. What is the probability that there is a least one man on the jury?" was all they asked

9 months agohm. 646645/646646 is more accurate, 99% could work too

9 months agoalright thanks so much for the help i really appreciate it!!

9 months ago