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mhchen:
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mhchen:
\[\sum_{n=1}^{\infty}\frac{-1}{n}\] So if there wasn't a -1. I would say you could use the p-series test where p=1 and it therefore diverges. But since there's a -1 in the numerator ah nvm I'm stupid I just realized my answer cause I can take the -1 out lol
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