Question

ortho/meta/para directors problem

Answer 1

since OMe is a strong activating O/P director and NO2 is a strong de-activating M director where should the NO2 from nitration go? :S

Answer 2

asked a tutor for you but he didn't want to come on QC and started lecturing at me smh

(pasting screenshots)

Answer 3

When you have two substituents, the more activating group takes priority for placement of the new thing.

So

where I drew the X wouldn't happen even though it's ortho to the more activating group (the OMe) because of steric hindrance

Para to the OMe would be your main product, but you'd still get some ortho to the OMe

Answer 4

So when you have two substituents, the product gets placed based on the more activating and OMe is clearly more activating compared to NO2