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Mathematics 14 Online
kaylak:

help calc

kaylak:

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kaylak:

@Vocaloid

Vocaloid:

since you want them to have the same value at x = 1, set the two parts equal to each other, plug in x = 1, and solve for a

Vocaloid:

still there? x^2 + 2x + a = lnx plugging in x gives 1^1 + 2(1) + a = 0 solve for a

kaylak:

e

Vocaloid:

check your signs again 1 + 2 + a = 0 then a must be -3 not 3

kaylak:

ok

kaylak:

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Vocaloid:

yikes well apart from the obvious (there are two zeros at x = 3 and x = 2 b/c of the denominator I wouldn't know how to do this w/o a graphing calculator. hm.

kaylak:

could i do a plug in method

Vocaloid:

you'd have to graph across the intervals to see which one doesn't have any jumps or discontinuities we can eliminate B and C because they contain the discontinuities at x = 3 and x = 2

kaylak:

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Vocaloid:

rate of change formula again [ f(5) - f(2) ] / (5-2) = ?

kaylak:

what is f?

Vocaloid:

the function.

kaylak:

I know it's over 3 and gotcha

Vocaloid:

f(5) means plug x = 5 into the function and evaluate f(2) means plug x = 2 into the function and evaluate then find f(5) - f(2) and divide the result by 3

kaylak:

so 15-3=12/3=4

kaylak:

1 attachment
Vocaloid:

you just have to plug in x = 1 and x = 2 to generate two points then after that it's just slope formula and basic algebra to find the slope and y-intercept

kaylak:

so -1,8

kaylak:

1 attachment
kaylak:

@Vocaloid

Vocaloid:

just need to take the derivative of the function and plug in x = 1

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