help calc
@Vocaloid
since you want them to have the same value at x = 1, set the two parts equal to each other, plug in x = 1, and solve for a
still there? x^2 + 2x + a = lnx plugging in x gives 1^1 + 2(1) + a = 0 solve for a
e
check your signs again 1 + 2 + a = 0 then a must be -3 not 3
ok
yikes well apart from the obvious (there are two zeros at x = 3 and x = 2 b/c of the denominator I wouldn't know how to do this w/o a graphing calculator. hm.
could i do a plug in method
you'd have to graph across the intervals to see which one doesn't have any jumps or discontinuities we can eliminate B and C because they contain the discontinuities at x = 3 and x = 2
rate of change formula again [ f(5) - f(2) ] / (5-2) = ?
what is f?
the function.
I know it's over 3 and gotcha
f(5) means plug x = 5 into the function and evaluate f(2) means plug x = 2 into the function and evaluate then find f(5) - f(2) and divide the result by 3
so 15-3=12/3=4
you just have to plug in x = 1 and x = 2 to generate two points then after that it's just slope formula and basic algebra to find the slope and y-intercept
so -1,8
@Vocaloid
just need to take the derivative of the function and plug in x = 1
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