Question

x^2+x+68=37x-3x^2-13 =>0

Answer 1

And no, I cannot/ not supposed to use the quadratic formula.

Answer 2

what you need to do with ?

Answer 3

Well so far I got 4x^2-36x+81

Answer 4

To equal 0

Answer 5

exactly very nice job

Answer 6

After that... I’m stuck

Answer 7

what is the question ? you need to solve it getting roots of this quadratic or what ?

Answer 8

What’s x to make it equal to 0

Answer 9

this mean that you need solve it for roots

Answer 10

I guess yea

Answer 11

do you know the way ?

Answer 12

It’s either 2x+? And 2x-? Or 4x+/-? And x+/- ?

Answer 13

4x^2 -36x +81 = 0

suppose rewrite it : in this above wrote way

Answer 14

4x*x -4*9x +9*9 = ?

Answer 15

??

Answer 16

any idea ?

Answer 17

No

Answer 18

4x^2 -36x +81 = 4x^2 -18x -18x +81 =

or you the discriminant method - do you know it ?

Answer 19

No

Answer 20

or use

Answer 21

D=b^2 -4ac

Answer 22

Nope

Answer 23

really ?

Answer 24

Yea

Answer 25

x_1,2 = (-b +/- sqrt(D) )/2a =

may be now ?

Answer 26

Nope

Answer 27

@ThisGirlPretty any help ?

Answer 28

Sadly no

Answer 29

without discriminant method

Answer 30

It’s ok

Answer 31

(2x-9)(2x-9) = ?

Answer 32

do you understand it now ?

Answer 33

4x^2 -36x +81 is a square perfect

Answer 34

(2x-9)^2

Answer 35

how you solve it now ?

Answer 36

write 2x-9=0

Answer 37

2x=9 and ?

Answer 38

divide both sides by 2 so what will get ?

Answer 39

x=9/2

so this the root of this quadratic

Answer 40

do you understand it now ?

Answer 41

ok

was my pleasure

bye bye