help
I don't think that's right... but the method I used might not be something you have learned yet can you tell me how you think you can do this problem? :)
sillybilly said c is wrong but I'm not sure how to do it then
people leave when Itag them
have you learned how to "derive" or "take the derivative" of equations yet?
yes and that is what confuses me
ok, so what did you get as the derivative? or would you like me to show you what I got?
show me please
ok so the concept is that derivative = equation of the slope in most cases in earlier math, you only see numerical slope (like the slope of straight lines) in these more complicated equations, the slope is also an equation (found by the derivative) the slope of a position function = speed the slope of a speed function = acceleration we are only looking for the speed function so we only "take the derivative" once
so -16 t^2 becomes -16(2) t = -32 t and 40 t becomes 40(1) = 40 so the equation for the slope is -32 t + 40 does this make sense?
ah okay so the answer is a
yup
correct?
eh eh eh not so fast
have you learned the power rule? like if you take the derivative of (x^2) you get (2 x) ?
yes
cool so what did you get from taking the derivative of x^2 - 3x + 6 ?
I have work with the first problem but I would have to take a picyure with my phone it's on paper
the derivative of x^2 - 3x + 6 is 2x - 3 is that what you got?
2x-3
yes
awesome and the equation is asking what is x when 2x - 3 = 1 ?
oh so 2
correct :)
well crap have to erase some stuff I'll do that but you can strat on next question
Step 1 take the derivative of x^2 + 2x - 2 Step 2 plug in x = 1 into the above result (this is your slope) Step 3 plug in slope = m and point = (h, k) into point slope form y - k = m (x - h) Step 4 simplify to get into slope intersect form
2x+2 4
mhm so the slope is 4
is e the answer then
yup!
really yay
I'm starting to understand lol
:blinks: ohhhh shot I forgot to read properly on the one before
cuz then C was right y = -(1/4)x + (5/4) because it's perpendicular I'm sorry ;-;
so c is right
yee
my bad
it's okay lol
then for the most recent problem it would be the same process of before derivative of 2x^2 - 5x + 1 then plug in x=1 to get the slope of the Tangent line
-1 is slope?
yup!
yay
I gtg now I've got my own pile of homework to do ;-;
aww well ty anyways
@Zarkon
try posting as a different thread that way potential helpers don't get confused on which problem you're working on
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