A small rocket is launched from a height of 6 feet off of the ground at an initial upward velocity of 64 feet per second. Its height is given by the equation -16t^2+64t+6, where h is the height of the rocket in feet and t is the time since liftoff in seconds. At what time is the rocket 54 feet in the air? ***question has been edited to provide missing information***

Question

Vocaloid · Answer

you are given height = 54 and asked to solve for t

therefore

54 = -16^2 + 64t + 6

subtract 54 from both sides and use graphing/factoring to solve for t