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Nicole:
@Vocaloid
Nicole:
@Shadow
Nicole:
@jhonyy9
Nicole:
@dude
Nicole:
I need help please lol
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dude:
You can graph this or just isolate y, which do you want to do?
Nicole:
isolate y..but how do we do that
dude:
Example for A:
\(5x+3y=4\)
Subtract 5x on both sides
\(3y=-5x+4\)
Divide by 3 on both sides
\(y=\large \frac{-5x+4}{3}\) or \(y=\large-\frac{5}{3}x+\frac{4}{3}\)
Nicole:
So its not A
dude:
Yep
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Nicole:
So for B:
5x-3y= -4
add 5x from both sides?
dude:
Subtract, you want to do the opposite operation
Nicole:
but we're subtracting for b so dont we add since its the opposite operation?
dude:
5x is positive
So you want to subtract it
Nicole:
3y= -5x - 4?
like that
im usually bad at this lmao
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dude:
Looks right, just remember to keep the sign of the 3y
dude:
\(-3y= -5x - 4\)
Nicole:
then what do I do?
dude:
Divide by -3 on both sides
Nicole:
-5x-4/3
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Nicole:
\[\frac{ -5x-4 }{ 3 }\]
dude:
\(y=\frac{5}{3}x+\frac{4}{3}\)
Nicole:
So its not b either
dude:
Neh
Nicole:
Now C
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Nicole:
4x+16y = -20
Subtract 4x from both sides
dude:
Yes
Nicole:
16y = 4x-(-20) im not sure
dude:
Close
\[16y=-4x-20\]
Nicole:
now divide both sides by 4?
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dude:
By 16, youre trying to get y by itself
Nicole:
y = \[\frac{ -4-20 }{ 16 }\]
Nicole:
-24/16
Nicole:
-1.5
Nicole:
so not C
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dude:
\(y=-\frac{1}{4}x-\frac{5}{4}\)
dude:
Yeh
dude:
\(6x+2y=-8\)
Subtract 6x on both sides
\(2y=-6x-8\)
Divide by 2 on both sides
\(y=-3x-4\)
dude:
Therefore D is your answer
Nicole:
got it
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