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Mathematics 44 Online
Nicole:

http://prntscr.com/kxfnbk

Nicole:

@Vocaloid

Nicole:

@Shadow

Nicole:

@jhonyy9

Nicole:

@dude

Nicole:

I need help please lol

dude:

You can graph this or just isolate y, which do you want to do?

Nicole:

isolate y..but how do we do that

dude:

Example for A: \(5x+3y=4\) Subtract 5x on both sides \(3y=-5x+4\) Divide by 3 on both sides \(y=\large \frac{-5x+4}{3}\) or \(y=\large-\frac{5}{3}x+\frac{4}{3}\)

Nicole:

So its not A

dude:

Yep

Nicole:

So for B: 5x-3y= -4 add 5x from both sides?

dude:

Subtract, you want to do the opposite operation

Nicole:

but we're subtracting for b so dont we add since its the opposite operation?

dude:

5x is positive So you want to subtract it

Nicole:

3y= -5x - 4? like that im usually bad at this lmao

dude:

Looks right, just remember to keep the sign of the 3y

dude:

\(-3y= -5x - 4\)

Nicole:

then what do I do?

dude:

Divide by -3 on both sides

Nicole:

-5x-4/3

Nicole:

\[\frac{ -5x-4 }{ 3 }\]

dude:

\(y=\frac{5}{3}x+\frac{4}{3}\)

Nicole:

So its not b either

dude:

Neh

Nicole:

Now C

Nicole:

4x+16y = -20 Subtract 4x from both sides

dude:

Yes

Nicole:

16y = 4x-(-20) im not sure

dude:

Close \[16y=-4x-20\]

Nicole:

now divide both sides by 4?

dude:

By 16, youre trying to get y by itself

Nicole:

y = \[\frac{ -4-20 }{ 16 }\]

Nicole:

-24/16

Nicole:

-1.5

Nicole:

so not C

dude:

\(y=-\frac{1}{4}x-\frac{5}{4}\)

dude:

Yeh

dude:

\(6x+2y=-8\) Subtract 6x on both sides \(2y=-6x-8\) Divide by 2 on both sides \(y=-3x-4\)

dude:

Therefore D is your answer

Nicole:

got it

dude:

:P

Nicole:

http://prntscr.com/kxgygd

Nicole:

C?

dude:

Make a new thread, this is going to get long

Nicole:

okay

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