Question

If a single-pane of glass with an area of 1.00 square meter and a temperature difference of 1.00 kelvin has a heat loss of 5.70 watts, then what is the heat loss through a single-pane window with an area of 2.50 square meters and a temperature difference of 20 kelvins?

Answer 1

had to look up the formula for this but it should be

h = k*a* deltaT
where h is heat loss, k is a constant, a is the surface area of the glass, and deltaT is the temperature difference

so you'd solve for k first by plugging in 1m^2 for a, 5.70W for heat, and 1 for deltaT

then you'd use that k value to find h for the second set of conditions