Question

Help with this concept (Cobwebbing)

Answer 1

uh

well I suppose you'd start with y = x and y = (your function) on the same xy plane

Answer 2

in this case (0,0) and (0,f(0)) are the same
then we'd go (0.25,0.25) and (0.25,f(0.25)) and draw the vertical line between these two
points

note: the interval would probably depend on your function though

Answer 3

then you'd go to the next value of (a1,a1) and draw a horizontal line
then draw a vertical line between (a1 and f(a1))

Answer 4

anyway you'd keep going with this process until the line y = x and y = (your function) meet at the same point

Answer 5

any point(s) where the two graphs intersect, those are your equilibria values

Answer 6

So its basically building the points onto one another

Answer 7

and just seeing where they meet

Answer 8

yes

Answer 9

Could you just go over sequencing real quick.

Answer 10

You just insert the previous term, right?

Answer 11

for a recursive sequence yes

Answer 12

a_n+1 is just a notation that means "next term" you don't literally add n + 1

Answer 13

wouldt it be the same regardless its still going up one?

Answer 14

a_n+1 = an^an

means start with the first term a1 = 2
for n = 2

"a_n+1" = "a_2" = 2^2

Answer 15

oh its squaring

Answer 16

then for a_3 we repeat the same pattern with 2^2

a_3 = (2^2) ^ (2^2)

Answer 17

you need to pay attention to the actual formula

a_n+1 = an^an

it's the "an^an" part that matters

Answer 18

so the n+ literally doesnt mean anything you have to pay attention to the expressions adter that?

Answer 19

okay i see

Answer 20

like, "a_n+1" means "the term after a_n"

Answer 21

yeah

for 256^256 you can just leave it like that

Answer 22

perfect thanks

Answer 23

something like that just to make sure

Answer 24

for the second one

Answer 25

yeah basically