Is this the same as regular sequencing?
it's asking for the equilibrium values so you need to set a_n+1 = a_n and solve for a
so for a) a_n+1 = 2a_n*e^(a_n) becomes a = 2a*e^a and solve for a
end up with 2?
e^2?
:S
hm, not quite, we just need to consider a = 0 makes both sides equal to 0 so 0 is the equilibrium value
is that in every case?
like does a=0 in every problem
no, you need to consider them on a case-by-case basis
so which value makes sense in the formula
yes, you need to solve for the a-value that makes a_n = a_n+1
okay
so it just needs to equal the given value in a way?
you need to take the equation, replace "a_n" and "a_n+1" with "a" and solve for a.
got it
is like x3 correct or should it be 3x
uh is it supposed to be 3^x in the logarithm or 3x
oh
x3 i think
yeah Idk about the second one
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