Question

Line JK passes through points J(–3, 11) and K(1, –3). What is the equation of line JK in standard form?

a.7x + 2y = –1
b.7x + 2y = 1
c.14x + 4y = –1
d.14x + 4y = 1

Answer 1

Eh you want to get the answers in slope-intercept form first

Then find the slope by using \(\large \frac{y_2-y_1}{x_2-x_1}\)

Answer 2

The slope is -14/4

Answer 3

\[\large{\frac{y_K-y_J}{x_K-y_J}}\]

Answer 4

thanks