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Given that f(x) = x2 − 4x − 3 and g(x) = the quantity of x plus three, over four , solve for f(g(x)) when x = 9. (1 point) −6 3 6 9
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\(g(x)=\frac{x+3}{4}\)
\(f(g(x))\) Basically means to substitute g(x) into f(x)
\(f(g(x))=\boxed{\frac{x+3}{4}}^2 − 4(\boxed{\frac{x+3}{4}}) − 3\)
@dude ahh okay thank you
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