Question

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http://prntscr.com/l4xw2y
Question
http://prntscr.com/l4xw5v

Answer 1

@Vocaloid

Answer 2

first step is to add 5 to both sides to the equation to get

2x^2 - 3x + 5 = 0

now, identify your a, b, c values using the general form

ax^2 + bx + c

and then plug a, b, and c into the discriminant b^2 - 4*a*c

Answer 3

a=2
b=3
c=-5

Answer 4

like that?

Answer 5

close, you switched the signs on b and c

2x^2 - 3x + 5 = 0

a = 2, b = -3, c = 5

Answer 6

so
-3^2-4*2*5

Answer 7

yeah just be careful with parentheses

(-3)^2 - 4*2*5

Answer 8

http://prntscr.com/l4y1du

Answer 9

how many solutions tho?

Answer 10

the discriminant is negative, so zero real number solutions

Answer 11

http://prntscr.com/l4y1w4

Answer 12

same logic as last time
subtract 12 from both sides to get

x^2 - x - 12 = 0

if it's also asking for the discriminant and number of solutions, repeat the same process as before

Answer 13

what would a b or c be? because they are all x

Answer 14

remember, if no coefficient is stated it is assumed to be 1

so a would be 1, b would be -1

c is the constant (-12)

Answer 15

is this correct
http://prntscr.com/l4y3ww

Answer 16

b should be -1 not 1

x^2 - x - 12 = 0, the second coefficient has a negative sign

Answer 17

(-1)^2 - 4(1)(-12) = 49

positive discriminant, so two real solutions