Write x^2 − 8x + 13 = 0 in the form (x − a)^2 = b, where a and b are integers. (x − 4)2 = 3 (x − 3)2 = 2 (x − 2)2 = 1 (x − 1)2 = 4
@jhonyy9
do you know formula (a-b)^2 = ?
yeah i think so
write it here please
yeah one sec
courage just like a first step
ya that will help
Would it be like this? (x-1)^a = 8
no
damnit ik where i messed up
you need to know formula (a-b)^2 = ?
the a would be 2
so nvm then ig idk it
ya i think so
a=2 not is right
hold on
it would be like this then cause i messed up (x-1)^2 = 8 right.....????????
and so how will get the 13 ?
ATTENTION please !
I am paying attention!!!!!! i was looking back at the damn problem!!!!
rewrite it in this way x^2 - 2*4x +13+3-3 = 0 bc. x^2 -8x +16 = (x-4)^2
from this result a=4 and so b = ?
I am just confused now this is retarded
ok. looke please (a-b)^2 = a^2 -2ab +b^2 yes ?
ig
so fro you can making from this x^2 -8x +13 perfect square of (x-4)^2 = x^2 -2*4x +16 what you need to do with 13 ?
you need adding to 13 a 3
Iḿma be honest i am completely confused and this is everywhere
but for you can adding this 3 you need subtracting it too for this expression not being modified
idk what to do and not to be rude but you are making this problem go everywhere
first of all you need making from x^2 -8x +13 a square perfect yes ?
this will be (x-a)^2
ok
you can rewriting this x^2 -8x +13 in this form x^2 -2*4x +13 yes ?
and bc. formula (a-b)^2 = a^2 -2ab +b^2 this mean that in place of b^2 you need getting 16 what is the square of 4
@Ultrilliam your opinion please
why dont wan believing me the asker that this is right ?
@Elsa213
@dude please
I don't think they understand you, I understand your goal and what you try to say but they don't I can try to help you out in terms of communicating with others, are you a native English speaker?
I got the answer
Okay
no my mather language is hungarian and second is roumanian bc. my birth country is Roumania but i live in Hungary
its (x-4)^2 = 3
yes exactly
thank you @dude
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