Geometry @Nicoley269

Okay they are both the same length
Meaning that they both have to be 12.5
\(3y-x=12.5\\ 2x-y=12.5\)
Do you understand?
Ok
So from here we can isolate y from \(3y-x=12.5\) Do you know how to do that?
No
(first, add x on both sides)
Ok
3y=12.5+x
Right and now divide by 3 on both sides
Y=4.16666.... +1/3x
Right you can leave it as a fraction but decimal is fine too Substitute it into the second equation \(2x-(\frac{12.5}{3}+\frac13x)=12.5\) Distribute and solve for x
Yes, now subtract 2x and 1/3x
5/3x-12.5/3=12.5
\(\frac53x-\frac{12.5}{3}=25\) Right so now add \(\frac{12.5}{3}\) and 25
ok... im not rly good with fractions
Get them to the same base (multiply 25 by 3) \(\large \frac{12.5}{3}+\frac{75}{3}\) That should help
ok o i would get 87.5/3
\(\frac53x=\frac{87.5}{3}\) Now we isolate x, we should get x=10
ok so we just plug it in. right?
I have to go rn but From here we can just substitute back into either equation Isolate y and we should get y=7.5 x= 10 y=7.5 \(3(7.5)-10=12.5\\ 22.5-10=12.5\)\(\checkmark\)
ok
thank you
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