Question

http://prntscr.com/l6ggch

Answer 1

@dude

Answer 2

All right

Answer 3

http://prntscr.com/l6gh0u

Answer 4

All right again

Answer 5

http://prntscr.com/l6gh53

Answer 6

Looks right

Answer 7

http://prntscr.com/l6ghnp

Answer 8

Looks good

Answer 9

LMAO MYB

Answer 10

That was for someone else

Answer 11

Yeah totally didnt see that coming

Answer 12

yeah me neither. deadass was going to someone else

Answer 13

sorry

Answer 14

http://prntscr.com/l6gjpo

Answer 15

Looks right and haha its okay

Answer 16

oof
http://prntscr.com/l6gkpj

Answer 17

Correct

Answer 18

http://prntscr.com/l6glch

Answer 19

Right

Answer 20

http://prntscr.com/l6gm3d

Answer 21

Correct

Answer 22

http://prntscr.com/l6gnph

Answer 23

*hugs and forever too*

Looks right

Answer 24

lmaooo

http://prntscr.com/l6gogt

Answer 25

Right lol

Answer 26

http://prntscr.com/l6gq7f

Answer 27

Question 40: correct

Answer 28

http://prntscr.com/l6gqcj

Answer 29

where'smymedal

No - domain is all x-values, only. See here

Answer 30

isnt it C?

Answer 31

That's not just \(x\) values. Those are ordered pairs

Answer 32

so A?

Answer 33

🎉

Answer 34

lolol

http://prntscr.com/l6grnh

Answer 35

Range is the \(y\) values, so you plug in the given domain (\(x\)-values) to get your answer.\[f(x)=3x-9\]When \(x=-2\), then \[y=3(-2)-9=-6-9=-15\]When \(x=0\), then \[y=3(0)-9=0-9=-9\]When \(x=3\), then \[y=3(3)-9=9-9=0\]