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Mathematics 39 Online
eviant:

PLS HELP!!! Determine whether the function ƒ(x) = x3 + x2 is even, odd, or neither.

eviant:

@mhchen

mhchen:

Well an even function is when f(-x) = f(x) an odd function is when f(-x) = -f(x) Try solving f(-x) first \[f(-x) = (-x)^3+ (-x)^2\] What do you get?

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