Question

calc help @vocaloid

Answer 1

Where's the question?

Answer 2

I will post but are you good in calc? I really need help!

Answer 3

I'm not good in calc.. however, I am taking the class as of now.

Answer 4

What level of calc are you taking?

Answer 5

ab

Answer 6

ap calculus?

Answer 7

I would think the graph goes like this

Answer 8

yes

Answer 9

Oh, I'm sorry, I wouldn't be much of help then. I'm taking pre-calc

Answer 10

@kittybasil do you know?

Answer 11

you commented and then deleted it ?

Answer 12

@shadow

Answer 13

@ZoeyBiocth16 js Shadow doesn't help in calc

Answer 14

ok note to self and thank u kitty

Answer 15

Yea, shadow doesn't offer help in that particular course-- you can still ask him if you'd like though.

Answer 16

@mhchen is online! yay!

Answer 17

is this the derivative?

Answer 18

It goes up by a constant slope.

Then it goes down by a constant slope.

Since the slope is the derivative. It's more like this:

Answer 19

ah okay could you help with 4 more really 2. I have 2 answered

Answer 20

ye

Answer 21

First one is correct.

Answer 22

The second one...

\[\sqrt{x} = x^{\frac{1}{2}}\]

Answer 23

Can you find the derivative of
\[x^{\frac{1}{2}}\]

Answer 24

1/2x^1/2

Answer 25

1/ 2x ^1/2

Answer 26

\[\frac{1}{2}x^{-\frac{1}{2}}\]

Don't forget the negative since
1/2 - 1 = -1/2

Answer 27

so still none of the above?

Answer 28

So the answer for 2 is
\[\frac{1}{2x^{\frac{1}{2}}} \]
or
\[\frac{1}{2 \sqrt{x}}\]

Answer 29

oh okay

Answer 30

For the third question.

You can rewrite it as

\[8x^{-\frac{1}{2}}\]

can you find the derivative of that?
Remember you multiply 8 by the exponent (-1/2)
and then you subtract 1 from the exponent.

Answer 31

-4x^-3/2

Answer 32

right?

Answer 33

Yup.

Now plug x=4 in for x to find f'(4)

Answer 34

-1/2 or d

Answer 35

Yeah

Answer 36

last one!

Answer 37

find the derivative?

Answer 38

Okay do you remember this formula:

\[(\frac{a}{b})' = \frac{a'b - ab'}{b^2}\]

Answer 39

yes

Answer 40

So yeah same thing:

\[\frac{x^2}{f(x)} \]
can you try and find the derivative of that

Answer 41

1/Y?

Answer 42

sorry caps lock lol

Answer 43

er i'm not sure where you got Y from..

\[(\frac{x^2}{f(x)})' = \frac{(x^2)'f(x) - (x^2)(f'(x))}{f(x)^2}\]

it should be like this instead.

Do you see what I did?

Answer 44

oh yeah I needed to put in that equation

Answer 45

makes sense since I have to plug in values

Answer 46

Yeah, just plug in the values for f(x) and f'(x) in that thing

Answer 47

isn't it false

Answer 48

unless I did something wrong I'm checking now

Answer 49

uh let me check..


6*2-9*4 / 4 = 12 - 36 / 4 = -24/4 = -6

Answer 50

yeah I think it's false.

Answer 51

hey that's what I got

Answer 52

welp that's it then

Answer 53

yay ty!