ANswer check
@Vocaloid
yeah that should be right
oh make sure you don't skip the second bullet point for #1
I wasn't sure how to do that one :S
it's the same logic, you just want Aa Bb, Dd instead it says that the E gene can be ee, Ee, or EE so that covers all possibilities so you only need consider the A, B, and D genes
and make punnet squares for them right
i mean like separate ones or combine them
you already made punnet squares so you just need to calculate the probability of AaBbDd based on what you already did
and add them?
1/2+1/2+1/2?
notice how you multiplied for the previous problem, right? so the calculation shouldn't be any different, you would multiply not add.
anyway when you get back, for #2 it's asking for the genotypes, not the probabilities you have a 3:1 ratio between the 4-pod green leaf + 4 pod-yellow leaf so you need to figure out what the genotypes of the parents are likely to be
oh okay got it 1.25%
1.25? I think you shifted a decimal place, 1/2 * 1/2 * 1/2 should be 1/8 = .125
so 12.5%
Okay yeah your right. OKay so for number 2 I would just do a punnet square the way I did and figure out the parents from that
it would be a waste of time to try and calculate each possible punnet square consider each trait separately: if all the resulting plants have 4 pods, not 3, what is the most likely genotype of the parents?
F
its more dominant
remember that genotypes have two alleles, so if there are only F alleles, both parents must be FF any ideas on the leaf color? 3:1 ration between green and yellow --> what genotypes?
Gg
awesome so FFGg
next one is a bit harder but since half have green leaves and half have yellow leaves what are your thoughts?
50/50
so um it would be FFGG?
hm, no, that would make every offspring have the same genotype
OH right okay so it would ge FfGg
I think :S
almost let's consider the traits separately we have a 3:1 ratio between 4-pods and 3-pods and a 1:1 ratio between yellow and green so thinking back to 2*2 crosses what genotype ratios give you these phenotype ratios?
remember, parents do not have to have the same genotype
Well FfGg gives 3:1, we know that
consider F and G separately
the F-allele must give a 3:1 ratio the G-allele must give a 1:1 ratio
Would I refer back to the square I made :S
think about a 2*2 cross two heterozygotes give a 3:1 ratio right? and a heterozygote + homozygous recessive gives a 1:1 ratio right? so putting this logic together, what must the genotypes of the parents be? you will have to write a different genotype for each parent
Okay so hetero would be FfGg and homo would be FG ?
:S
OHhh
I know
both of them are heterozygotes for F --> both are Ff for G, one of them is a heterozygote and the other is a homozygous recessive --> one of them is Gg and the other is gg
now try writing out the full genotypes
FfGg Ffgg
good since it asks to show the crosses, you would show the crosses for the genotypes we determined so for A show FFGg * FFGg and for B show FfGg * Ffgg
like, the punnet squares
would this be 2x2 or 4x4
these are dihybrid crosses so 4x4
THe crosses would be FG, Fg, Gg, gF?
the double ff's are throwing me off when im drawing the square
Like at the top of the swuare those would be the 4 values right
almost (personally I'd write the F's first to get FG, Fg, FG, Fg)
since both parents in A have the same genotype, the left side is also the same 4 allele combos
remember you group the same letter together when you write genotypes FFGG not FGFG
wait this would be part A right :S
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Vocaloid good since it asks to show the crosses, you would show the crosses for the genotypes we determined so for A show FFGg * FFGg and for B show FfGg * Ffgg \(\color{#0cbb34}{\text{End of Quote}}\)
that's part B
\\(\color{#0cbb34}{\text{Originally Posted by}}\) @Vocaloid good since it asks to show the crosses, you would show the crosses for the genotypes we determined so for A show FFGg * FFGg and for B show FfGg * Ffgg \(\color{#0cbb34}{\text{End of Quote}}\)
but either way you need to re-do your part A anyway since you wrote the genotype alleles in the wrong order
so this is right for part B
\\(\color{#0cbb34}{\text{Originally Posted by}}\) @Vocaloid good since it asks to show the crosses, you would show the crosses for the genotypes we determined so for A show FFGg * FFGg and for B show FfGg * Ffgg \(\color{#0cbb34}{\text{End of Quote}}\) part A asks for FFGg * FFGg, you wrote that in the part B slot instead
copy the FFGg * FFGg punnet square into part A, then for part B write the FfGg * Ffgg punnet square
are these the right crosses for Part B
for top parent: should be FG Fg fg fg (change the third one) for other parent: Fg Fg fg fg (notice how there are no capital G's since parent 2 has no capital G alleles)
BUt there is a capital F. that wouldn't matteR?
the f allele does not influence the g allele
Got it finally
SO for this problem its only asking for the ratio
how would I determine whether its asking for the ratio or the percentage
what no, it's asking for the genotypes, you need to know the ratios to be able to find out what the genotypes are if it wants the ratios/percentages it will ask for them
no no . i meant in any given problem
nvm
it'll specify ratios or percentages, if not, either is acceptable since they both are just different ways to express the same thing
I think ratios would be better though
perfect thanks
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