Question

?

Answer 1

you have two traits (outer kernel color and endosperm color)

if both parents are heterozygous for both traits, as stated in the question, the cross must be between AaEe * AaEe so make your punnet square based on that

Answer 2

kernel color (if purple) masks the color of the endosperm so this is epistasis not incomplete dominance

Answer 3

so would it be AE, Ae, ae, and aE

Answer 4

yes

Answer 5

for the top and left of the square

Answer 6

yes

Answer 7

check the second row and column again

it has to be Ae not Aa

Answer 8

good

now, since this is an epistatic trait the phenotype ratios are a bit different than usual

any purple will mask the endosperm, so anything with AA or Aa will be purple regardless of what the E is

then, aaEE and aaEe make yellow since yellow is the dominant trait that occurs in the absence of purple

and aaee will be white

calculate the percentages based off that

Answer 9

purple = 75%
yellow= 18.75%
white= 6.25%

Answer 10

good that's it