zarkam21:

?

2 weeks ago
zarkam21:

1 attachment
2 weeks ago
Vocaloid:

you have two traits (outer kernel color and endosperm color) if both parents are heterozygous for both traits, as stated in the question, the cross must be between AaEe * AaEe so make your punnet square based on that

2 weeks ago
Vocaloid:

kernel color (if purple) masks the color of the endosperm so this is epistasis not incomplete dominance

2 weeks ago
zarkam21:

so would it be AE, Ae, ae, and aE

2 weeks ago
Vocaloid:

yes

2 weeks ago
zarkam21:

for the top and left of the square

2 weeks ago
Vocaloid:

yes

2 weeks ago
zarkam21:

1 attachment
2 weeks ago
Vocaloid:

check the second row and column again it has to be Ae not Aa

2 weeks ago
zarkam21:

1 attachment
2 weeks ago
Vocaloid:

good now, since this is an epistatic trait the phenotype ratios are a bit different than usual any purple will mask the endosperm, so anything with AA or Aa will be purple regardless of what the E is then, aaEE and aaEe make yellow since yellow is the dominant trait that occurs in the absence of purple and aaee will be white calculate the percentages based off that

2 weeks ago
zarkam21:

purple = 75% yellow= 18.75% white= 6.25%

2 weeks ago
Vocaloid:

good that's it

2 weeks ago
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