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Chemistry 87 Online
Vocaloid:

Just want to check if I did this NMR analysis right

Vocaloid:

spectrum of the compound |dw:1540340196918:dw| structure of the compound (far right) |dw:1540340213844:dw| my attempt at identifying the important peaks |dw:1540340257332:dw|

Vocaloid:

as usual please do not comment unless you are actually attempting to solve the problem @imqwerty @Tranquility if it wouldn't be too much trouble could you check my work?

HuskyNation:

What course is this because I have several college friends

Tranquility:

I'm really not to sure about the ingerprint region since we never eally studied it in detail. We weren't required to memorize any of those values in the finger print region since they tend to be specific to each compound so I'm not really sure about those <1400 values. However, I think instead of using carbonyl, you should use ester, or better yet anhydride. This website has a pretty comprehensive list of all the IR values https://www.cpp.edu/~psbeauchamp/pdf/spec_ir_nmr_spectra_tables.pdf

Vocaloid:

that's kind of what I was thinking @ first but my peak is at 1780 which puts it a bit outside the normal ester range but would it be ok to label it as an ester instead?

Tranquility:

I think for it to be an ester, it needs to have 1 R group so anhydride is best. And in this case, the anhydride has formed a 5 member ring. And if you look at the link, on page 2: 5 atom ring = 1785, 1865 And in your IR, you do have a 1780 and 1860 band

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