Question

Lab Report: Genetic Crosses 1

Apply your understanding of how alleles assort and combine during reproduction to evaluate a scenario involving a monohybrid cross.

You may wish to construct the Punnett squares on scratch paper first before you fill in the Punnett squares on the Lab Report. Answer the questions below. When you are finished, submit this assignment to your teacher by the due date for full credit.

Part 1: Monohybrid Cross—Predicting Freckles in an F1 Generation
Apply your understanding of how alleles assort and combine during reproduction to evaluate a scenario involving a monohybrid cross.
The allele for having freckles (F) is dominant over the allele for not having freckles (f). Some characteristics in people are inherited as simple dominant and recessive traits. One example is freckles. Freckles is a dominant trait, and the lack of freckles is a recessive trait. In this example, a person with freckles is represented as either FF or Ff, and a person with no freckles is represented as ff.

1. Imagine a mother and a father who both have freckles and are heterozygous for the trait, or Ff. They are the P generation, or parent generation. Create a Punnett square to show their offspring, the F1 generation.

Answer:

Part 1 Punnett Square

Calculate the ratios of the genotypes and phenotypes of the offspring in the F1 generation.

Answer:

Genotypes:
Phenotypes:

Answer 1

@SmokeyBrown

Answer 2

Ok, do you know how to draw a punnett square?

Answer 3

yes exactly hold on one second

Answer 4

i might be blurry but it's like this

https://splits.s3.amazonaws.com/d34efc53847fcc94d5e216ec4c15fc5a7868d005/splits/v9/split-0-page-1-html-bg.jpg?X-Amz-Content-Sha256=UNSIGNED-PAYLOAD&X-Amz-Algorithm=AWS4-HMAC-SHA256&X-Amz-Credential=AKIAIAYW2E6VOLDTI35A%2F20181025%2Fus-east-1%2Fs3%2Faws4_request&X-Amz-Date=20181025T163402Z&X-Amz-SignedHeaders=host&X-Amz-Expires=604800&X-Amz-Signature=9c165228c78f345aa4066c1369dd3a0ecbca9d601544672ae7613fa9fddd49c1

Answer 5

Right. So since the mother and father are both Ff, the both have a 50% chance of contributing a dominant F allele and a 50% chance of contributing a subordinate f allele.
That means that there's a 25% chance that the child will have FF, a 50% chance the child will have Ff, and a 25% chance that the child will have ff as their genotype.
Since freckles are a dominant trait, both FF and Ff lead to the phenotype expressed as having freckles. So, there's a 25% + 50% = 75% chance the child will have freckles and a 25% chance that they will not.

Answer 6

which should i put for number 1 and number 2

Answer 7

Well, the genotype is the way that the alleles are written in the DNA, so that would be the information about chances for FF, Ff, and ff.
The phenotype is how the genes are expressed through physical traits, so that would be the information about chances for having freckles

Answer 8

1: So since the mother and father are both Ff, the both have a 50% chance of contributing a dominant F allele and a 50% chance of contributing a subordinate f allele.
That means that there's a 25% chance that the child will have FF, a 50% chance the child will have Ff, and a 25% chance that the child will have ff as their genotype.
Since freckles are a dominant trait, both FF and Ff lead to the phenotype expressed as having freckles. So, there's a 25% + 50% = 75% chance the child will have freckles and a 25% chance that they will not.

2:

Genotypes: the genotype is the way that the alleles are written in the DNA, so that would be the information about chances for FF, Ff, and ff.

Phenotypes: The phenotype is how the genes are expressed through physical traits, so that would be the information about chances for having freckles

Answer 9

should i have like this ?

Answer 10

Calculating the ratios of the genotypes and phenotypes of the offspring in the F1 generation: That means that there's a 25% chance that the child will have FF, a 50% chance the child will have Ff, and a 25% chance that the child will have ff as their genotype.
Since freckles are a dominant trait, both FF and Ff lead to the phenotype expressed as having freckles. So, there's a 25% + 50% = 75% chance the child will have freckles and a 25% chance that they will not.

Answer 11

I think the first part would just be a picture of your punnett square, and the second part would be the percent values for genotype and phenotype

Answer 12

i can't draw a punnett square very well

Answer 13

Something like this

Answer 14

so the question says just to write that

Answer 15

Yeah I think so, the question asks to draw a punnett square

Answer 16

https://splits.s3.amazonaws.com/d34efc53847fcc94d5e216ec4c15fc5a7868d005/splits/v9/split-0-page-1-html-bg.jpg?X-Amz-Content-Sha256=UNSIGNED-PAYLOAD&X-Amz-Algorithm=AWS4-HMAC-SHA256&X-Amz-Credential=AKIAIAYW2E6VOLDTI35A%2F20181025%2Fus-east-1%2Fs3%2Faws4_request&X-Amz-Date=20181025T163402Z&X-Amz-SignedHeaders=host&X-Amz-Expires=604800&X-Amz-Signature=9c165228c78f345aa4066c1369dd3a0ecbca9d601544672ae7613fa9fddd49c1

Part 1 Punnett Square

2. Calculate the ratios of the genotypes and phenotypes of the offspring in the F1 generation.

Answer:

Genotypes:
Phenotypes:

Answer 17

So, the first child generation, we have 25% FF, 25% ff, and 50% Ff for genotype
For phenotype, we get 75% has freckles, 25% do not have freckles