http://prntscr.com/lcwxgg
@Vocaloid @dude
@sillybilly123
You probably want to re-write them in slope-intercept form \((y=mx+b)\) Do you know how to do that?
Im not sure
You want to isolate the y-variable Ex. 1 one \(2x-y=-5\) Opposite of +2x is subtracting 2x \(-y=-2x-5\) I presume you know what to do from here, no?
Ex. 2 2x+y=5 Opposite of +2x is subtracting 2x +y=-2x+5
right @dude
Yes that is the second equation, there was 1 step missing in the one I did, I thought you were going to notice it \(-y=-2x-5\) Divide both sides by -1
okay so what do we do next
Set them equal to each other \(2x+5=-2x+5\) Now solve for x
x=0
That is the solution
So its none (B
I just said that is your solution haha x=0 is the solution not to be confused with x being cancelled out (in which it would not have any)
Solution is where they intersect, look at the x and y value at where they touch
(6,-6)
The x-coordinate is not right, it is below 5
if its below 5 it would be 4
@Bob @563blackghost @dude
@Vocaloid
nice mass tag gril
lmao i need help asap
Close, each line goes up by 1
evil hamster man
im confused lmao
3
Yes (3,-6)
A
wow diwect answugh
Right
Boi that was not direct answer smh
that wasnt direct
wOt iT wAsNT ?
Do you know how to graph?
not that lol
so first you can plug the y values and x values of each of the choices into the first equation let's start with A y = x - 1 3 = 4 - 1 now B y = x - 1 4 = 3 -1 now C y = x - 1 -3 = -4 - 1 now D y = x - 1 -4 = -3 - 1
@Nicole which choices are true when plugging in the y and x values
@dude she's gone she was so desperate she left
"she was so desperate she left" ok lol
u gonna answer
C or D?
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