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What is the equation of a line that passes through the point (1, 8) and is perpendicular to the line whose equation is y=x2+3 ? MY ANSWER y=-2x+10
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@Shadow can you check my answer please
@umm
what is x2
slope?
Yeah but that looks like x^2 which is a parabola
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that doesnt have a slope, so I assume you wrote the slope incorrectly.
i did oops its x/2
yes
Thanks Shadow the answer was y=-2x=10
Point-Slope Form \[y - y_{1} = m(x - x_{1})\] \[y - 8 = -2(x - 1)\] \[y - 8 = -2x + 2\] \[y = -2x + 10\] Yeah you're correct.
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Thank you i made an 80 on the quiz cuz i got that question wrong
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