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If f(x)=1/2x-6, what is the equation for f^-1(x)?
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f(x)=\[\frac{ 1 }{ 2}\]x-6
@dude
\(f(x)=\large \frac{ 1 }{ 2}x-6\) Flip x and y and then solve for y \(x=\large \frac12y-6\)
x-6=1/2y
@dude
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ADd 6 on both sides
x-6+6=1/2y+6 x=1/2y+6
@dude
No no I meant \(x+6=\frac12y\)
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