Question

If l||m and m∠6 = 4x - 15 and m∠7 = x + 30, then m∠6 =

15
45

Answer 1

given line m II line l
and
m<6 = 4x-15 and m<7 = x+30

line t intersect line m and l so from this result that m<6 = m<7 so

=> 4x-15 = x+30
3x = 45

x = 45/3

x = 15 so using this value of x => m<6 = 4x-15 so m<6 = 4*15 -15 so m<6 = 45 degree

hope helped