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What is the equation of a line that is perpendicular to 2x+y=−4 and passes through the point (2, −8) ?
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\[y-(-8)=1/2(x-2)\]
\[y=1/2(x-2)-8\]
Answer \[y=1/2x-9\]
\[2x + y = -4\] \[y = -2x - 4\] Slope: -2, Perpendicular -> 1/2 Good It seems your x and y went in the right spots
1/2 times -2 = -1 Though it becomes +8 on the left side
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So -1 - 8 = -9, looks good
Thank you shadow
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