Can someone answer these questions for me?
I can't answer them for you, but I can help you get to the answer
I meant that
So the general equation of a line is \(y=mx+b\) m is the slope b is the y-intercept So for question 11, we have -3 as a slope and -5 as our y-intercept Do you know how to substitute that?
no i do not
m is slope, so m is -3 b is the y-intercept, so b is -5 \(y=-3x-5\) Does that make sense?
yea, that makes sence
what about the other ones?
12 through 16
Just try #12 Maybe it will make sense if you try it
ok, ill try
Try it, if you cannot still understand it, then I'll walk you through
ok, thx
so, i think that #12 is y=0x-5?
Right! So anytime any value is 0, we just take it out \(y=-5\) is fine as well (we only removed the 0x since it does not mean anything)
ok, I think i understand it
Nice :P If you want me to check your work, I'll be here
so what would #11 be since it has a fraction
#13 you mean?
oh, yea
Pretend its a whole number, it follows the same rule of going in-front of the x
umm...... i dont understand.......sorry
Pretend its a whole number Slope is \(-\frac13\) = m y-intercept is \(5\) = b \(y=-\frac13x+5\) Nothing to simplify, that's all
no
Wut
nvrm
im still stuck on #13
Okay, does the fraction confuse you?
yea
Okay so think as the fraction as any normal number You don't have to change it in any way You just place it directly in for m
ok
Did that make sense? Or do you want me to make a sample question?
yea, a sample questionj might work
well..... sorry i have to go to bed
Okay, get some rest Night
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