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Mathematics
eviant:

PLS HELP!!!

6 months ago
eviant:

1 attachment
6 months ago
eviant:

@jhonyy9

6 months ago
jhonyy9:

27= 3^?

6 months ago
jhonyy9:

please collaborate

6 months ago
jhonyy9:

you need rewriting the 27 in exponential form like exponent of 3

6 months ago
jhonyy9:

27=3*3*3 = 3^?

6 months ago
jhonyy9:

courage

6 months ago
jhonyy9:

27=3^3 using this rewrite the original expression

6 months ago
eviant:

I don't understand

6 months ago
jhonyy9:

in your original - given expression in place of 27 write 3^3 ok ?

6 months ago
eviant:

ok

6 months ago
eviant:

(3*3x^-9)

6 months ago
jhonyy9:

no 27 = not 3*3 27 = 3 on power of 3

6 months ago
eviant:

(3^3x^-9)

6 months ago
jhonyy9:

yes but us parantheses [(3^3)*x^-9]^(1/3) = ?

6 months ago
jhonyy9:

(a*b)^x = (a^x)*(b^x) us this

6 months ago
eviant:

9/x^9

6 months ago
jhonyy9:

no the first pert will be (3^3)^(1/3) = ?

6 months ago
jhonyy9:

first part

6 months ago
eviant:

3

6 months ago
jhonyy9:

before i ve wrote to you that (a^x)^y = yes nice

6 months ago
jhonyy9:

so the second term how will be ?

6 months ago
jhonyy9:

(x^-9)^(1/3) = ?

6 months ago
eviant:

1/x^3

6 months ago
jhonyy9:

bc. there is this minus so this mean that you get 1/(x^9)^(1/3) = ?

6 months ago
jhonyy9:

yes exactly

6 months ago
jhonyy9:

how you ve got it ?

6 months ago
eviant:

so,the answer is 3/x^3

6 months ago
eviant:

right?

6 months ago
jhonyy9:

yes bc. dont forgot there is again the first term from what resulted 3

6 months ago
jhonyy9:

this is clearly now ?

6 months ago
eviant:

yes thanks

6 months ago
jhonyy9:

my pleasure

6 months ago
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