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eviant:
PLS HELP!!!
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eviant:
eviant:
@jhonyy9
jhonyy9:
27= 3^?
jhonyy9:
please collaborate
jhonyy9:
you need rewriting the 27 in exponential form like exponent of 3
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jhonyy9:
27=3*3*3 = 3^?
jhonyy9:
courage
jhonyy9:
27=3^3
using this rewrite the original expression
eviant:
I don't understand
jhonyy9:
in your original - given expression in place of 27 write 3^3
ok ?
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eviant:
ok
eviant:
(3*3x^-9)
jhonyy9:
no
27 = not 3*3
27 = 3 on power of 3
eviant:
(3^3x^-9)
jhonyy9:
yes but us parantheses
[(3^3)*x^-9]^(1/3) = ?
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jhonyy9:
(a*b)^x = (a^x)*(b^x)
us this
eviant:
9/x^9
jhonyy9:
no
the first pert will be
(3^3)^(1/3) = ?
jhonyy9:
first part
eviant:
3
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jhonyy9:
before i ve wrote to you that (a^x)^y =
yes nice
jhonyy9:
so the second term how will be ?
jhonyy9:
(x^-9)^(1/3) = ?
eviant:
1/x^3
jhonyy9:
bc. there is this minus so this mean that you get
1/(x^9)^(1/3) = ?
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jhonyy9:
yes exactly
jhonyy9:
how you ve got it ?
eviant:
so,the answer is 3/x^3
eviant:
right?
jhonyy9:
yes bc. dont forgot there is again the first term from what resulted 3
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jhonyy9:
this is clearly now ?
eviant:
yes thanks
jhonyy9:
my pleasure
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