The shape of a roller coaster is modeled by a polynomial function, R(x). Describe how to find the x-intercepts of R(x) and how to construct a rough graph of R(x) so that the engineer can predict when there will be no change in the direction of the coaster. You may create a sample polynomial of degree 3 or higher to use in your explanations.
Polynomial Equation: R(x)=4x^3+2x^2-7 Degree: 3 We then Plug in 1.059 in as X so it would look like R(1.059)=4(1.059)^3+2(1.059)^2-7 This then Equals R=-0.00608544 ^what i have so far
@Mehek
You will need three roots for this, so we have Let x = -30, -10 and +20 So the factors will be (x+30)(x+10)(x-20) The divide it to 100, this will help bring the peak up and down So the polynomial function R(x) will become 1/100 * (x+30)(x+10)(x-20) R(x) = 1/100 * (x+30)(x+10)(x-20) Finding the X-intercept: Let R(x) = 0 and solve for x. 1/100 * (x+30)(x+10)(x-20) = 0 x = -30, -10, 20 are the x-intercepts.
-.- i dun want copy and pasted answers i need actual help
You find x-intercepts by first factoring then solving for x
and if you can't factor you use the quadratic formula
Wait ok so whatt and how am i factoring
Factoring 4x^3 + 2x^2 - 7
ok hold on let me do it e.e
I dont think you can factor this
Right so then you use the quadratic formula
if i did it correctly it would be x=1.059 which i added as X
Polynomial Equation: R(x)=4x^3+2x^2-7 Degree: 3 I Tried to factor 4x^3+2x^2-7 but it didnt work so i used the quadratic formula which equaled x=1.059 which we Plug in 1.059 in as X and made y zero so it would look like R(1.059)=4(1.059)^3+2(1.059)^2-7
\(\bf{x=\dfrac{-b±\sqrt{b^2-4ac}}{2a}}\)
huh?
That's the quadratic formula
a is the coefficient of the first term, b is the second, c is the third
......
i thought i already solved it i said it was 1.059 am i wrong?
\(\bf4x^3+2x^2-7\) where a = 4 b = 2 c = -7
oop i didn't see the reply
so i am right ?
Yes
So that's where the graph intercept the x-axis
wait whats next? if the equation looks like this what do i do? R(1.059)=4(1.059)^3+2(1.059)^2-7
That gives you the point for the x-intercept (1.059, R(1.059))
Since you found what x is equal to you don't need to plug it in because that's all you do for the x-intercept
Polynomial Equation: R(x)=4x^3+2x^2-7 Degree: 3 I Tried to factor 4x^3+2x^2-7 but it didnt work so i used the quadratic formula which equaled x=1.059 This then gives use the point for the x-intercept (1.059, R(1.059)) ^is that all i have to do?
You can put (1.059, 0) cause it's the same thing
And yes that's all
For the first part
First part? what else do we have to do?
"Describe how to find the x-intercepts of R(x) and `how to construct a rough graph of R(x) so that the engineer can predict when there will be no change in the direction of the coaster`."
would it look like this?
Yeah but you have to say how you can construct it So first you'd plot the x-intercept Then you'd find the y-intercept which is plugging all the x with 0 and getting -7 so you'd plot (0,-7)
Have you learned how to find the minimum/maximum of a graph?
wait ok hold up so That way you can construct this graph is to first plot the x intercept which is 1.059 then you find the y intercept which is -7 because you plug everything in x with 0 which gives you -7 this would make your graph Decrease and go down.
Ummmm i probably did but forgot e.e
Correct
so would that be the answer for part 2
to find min/max \(\bf x= \dfrac{-b}{2a}\)
Yeah it would but it also mentions changes in direction so idk if you need the min/max
It changes direction as it decreases would that work
Yeah ig that works
Thank you would you possibly be able to help me with a few more e.e
ill make sure yew get lots of medals >.<
Gee I still helped 😒😒
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