An old-fashioned Chinese restaurant offers a family dinner where you get to choose one dish from “column A” (which has 8 dishes), one dish from “column B” (which has 10 dishes) and one dish from “column C” (which has 5 dishes). How many different family dinners can be chosen?

There are
a0possible dinners.

Question

An old-fashioned Chinese restaurant offers a family dinner where you get to choose one dish from “column A” (which has 8 dishes), one dish from “column B” (which has 10 dishes) and one dish from “column C” (which has 5 dishes). How many different family dinners can be chosen?

There are 
a0possible dinners.

bonez · Answer

don't think I can state it any clearer.  multiply the number of dishes in column A by the number of dishes in column B by the number of dishes in column C

bonez · Answer

400 would be the answer i believe