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Mathematics 7 Online
CC12:

Math help please

CC12:

1 attachment
Mehek:

You would first find <E It would be done like this: 18- <C - <D = <E

Mehek:

180 - <C - <D My bad I put 18

CC12:

102

Mehek:

Correct so <E = 102 <E is part of the second triangle too so both sides have 102 as their degree Hold on while I draw so you can understand it better

Mehek:

|dw:1543511808220:dw| so from what you should know, all the three angles in a triangle must add up to 180 degrees. We had two of the angles, <C and <D, so then we got <E

CC12:

60

CC12:

102+18=120-180=60 degrees ?

Mehek:

|dw:1543511887504:dw| opposite angles are equal, so <E for the other triangle is 102 as well. We have the second angle which is 18 180 - 102 - 18 = 60 Yes you are correct

CC12:

Thank you so much

Mehek:

no problem :)

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