Question

y = –x + 4
x + 2y = –8
How many solutions does this linear system have?

one solution: (8, 0)
one solution: (0, 8)
no solution
infinite number of solutions

Answer 1

\[x + 2(-x + 4) = -8\]
\[x -2x + 8 = -8\]
\[-x + 8 = -8\]
\[x -8 = 8\]
\[x = 16\]
\[y = -16 +4 = -12\]

x = 16
y = -12
(16, -12)

That is one solution, but is not represented in your answer choices...