PLS HELP!!!
@jhonyy9
any idea ?
no
\[y = \sqrt{25x-125} +5 \]
inside radical what can you factorizing out ?
please collaborate i not can giving you right answer directly
5?
attention - please chek it again - just 5 ?
125=5*25
so what are we factorizing out?
25x-125 = 25x-25*5
oh ok got it
we subtract 125x from each side?
which leaves us 25?
no 25x-125 = 25x-25*5 = 25(x-5)
ok, then what?
sqrt25 = ?
5
yes - sure - this is easy so than sqrt[25(x-5)] = ?
5sqrt(x-5)
yes so in this way how you can rewriting the first equation ? y = ?
y=5sqrt(x-5)+5?
yes exactly
so which one is the answer then?
how you think ? for x=5 what you get for y coordinate ?
5sqrt(x)?
so, the first option?
no substitute in place of x this 5 and calcule what will get for y
so the last option is the correct one?
why the last one ? you have x=5 not -5 so from this result that the graph not can being translataed 5 units left never
ok, so it can't be translated left right? so we can take out B and D out of the correct choices
so then it's C?
yes sure bc. x=5 so this mean right and y=5 what mean up but this is clearly to you now sure ?
yep thankx
sorry i ve forgat the 5 in front of radical so the first choice is right sure hope you understand it now clearly ok. ?
\(\color{#0cbb34}{\text{Originally Posted by}}\) @eviant y=5sqrt(x-5)+5? \(\color{#0cbb34}{\text{End of Quote}}\) so bc. how you see there in front of radical there is this 5 from what result that the last two choices not can being right
ok
good luck bye bye
do you have again questions ?
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