Question

PLS HELP!!

Answer 1

@Vocaloid

Answer 2

One of your exponent rules will allow you to rewrite the base like this,\[\large\rm \frac{1}{e}\quad=\quad e^{-1}\]

Answer 3

So then we can apply another exponent rule,\[\large\rm (x^a)^b=x^{ab}\]

Answer 4

If we apply that to our problem,\[\large\rm \left(e^{-1}\right)^x\quad=\quad e^{-x}\]

Answer 5

So we can see that, yes, we have an exponential,
with a base of e.

Answer 6

@Zepdrix thankx for explaining it so well