Oliver transforms the graph of y = 3x into the graph of y = 3x + 6. Which statements correctly describe this transformation? It is the graph of y = 3x translated 6 units upward. It is the graph of y = 3x compressed horizontally 6 units to the left. It is the graph of y = 3x translated 2 units to the left. It is the graph of y = 3x translated 6 units downward. It is the graph of y = 3x translated 6 units to the right. It is the graph of y = 3x stretched vertically 3 units upward.
do you have any idea in this case ?
what mean this +6 for y ? like a first step for x=0 you get for y = 6 so what mean this for the graph ?
i hope this helps Answer It is the graph of y = 3x translated 6 units upward. Explanation The general equation for a straight line is y = mx + c where m and c are gradient and y-intercept respectively. The graph of y = 3x is a straight line with a positive gradient of 3. It passes the origin. The graph y = 3x + 6 is a straight line with the same gradient of positive 3. But this graph passes through the point (0,6). That is it cats the y-axis at 6. So, the graph of y = 3x translated 6 units upward.
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