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briiijwonder:
Given a regular square pyramid with RS = 6 and PX = 4, find the following measure. XT = https://treca.owschools.com/media/g_geo_ccss_2016/5/groupi93.gif
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Bearclaws72:
@Vocaloid I don't do math
lowkey:
You know what a pyramid is?
lowkey:
|dw:1544659907714:dw|
briiijwonder:
yes
briiijwonder:
here is the image https://treca.owschools.com/media/g_geo_ccss_2016/5/groupi93.gif
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lowkey:
Okay, do you know how to start this
briiijwonder:
no
briiijwonder:
would is be square root 52
Vocaloid:
XT? I don't think so just look at the bottom side of the pyramid |dw:1544660476899:dw|
Vocaloid:
|dw:1544660516100:dw|
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Vocaloid:
XT is the hypotenuse of a right triangle w/ legs 3 and 3, just apply the pythagorean theorem
briiijwonder:
i did that was my answer
Vocaloid:
c^2 = 3^2 + 3^2 c = ?
briiijwonder:
18?
Vocaloid:
almost, don't forget to take the square root at the end
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briiijwonder:
ok thx
briiijwonder:
18^2
Vocaloid:
square root, not square
briiijwonder:
ok
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