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@Hero
The odds in favor of an event is \(m:n\). The probability the event will occur is \(\dfrac{m}{m + n}\). In this case we can let \(m\) represent the number of successes and \(n\) represent the number of failures. They give us that the probability of winning the split bet is \(\dfrac{1}{19}\) In other words we can expect to win one time out of \(19\) tries which implies \(1\) win + \(18\) losses to get to \(19\) total attempts. From here I think you can figure out what the ratio is.
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