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If f(x) = x2 -1, what is the equation for f^–1(x)?
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@dude
To solve for its inverse, you have to flip the x and y and then solve for y \(f(x) = x^2 -1\) f(x) is the same as y \(y = x^2 -1\) Now flip \(x=y^2-1\)
And then solve for y
@dude how do I solve for y?
Add 1 to both sides
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x+1=y^2?
Yes Now do the square root on both sides
x=-1+y^4?
wut
No \(\sqrt{x+1}=\sqrt{y^2}\)
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x=-1+y^2
I am not sure what you did It is just \(\sqrt{x+1}=y\) or \(y=\sqrt{x+1}\) The inverse is a square root function
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