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Solve for x: |x − 2| + 10 = 12 x = 0 and x = 4 x = −4 and x = 0 x = −20 and x = 4 No solution
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|x − 2| + 10 = 12 Solve so that the absolute value is left to itself |x-2|=2 the solutions can then be |x-2|=2 or |x-2|=-2
so it is C @dude
No
Bruh lol do you know how to solve it?
try to not give direct answers but yes You have to at least try to answer the questions lol We dont be here to help you pass your tests lol
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