Question

Consider the following code segment. What is the value of x after execution of the code?

double [] numList = {4.17, 3.11, 2.46, 1.57};
int x = 0;
for(double n : numList)
{
x += (int)n * 2;
}

Answer 1

@Ultrilliam

Answer 2

I put 23

Answer 3

for future reference:
```c
double [] numList = {4.17, 3.11, 2.46, 1.57};
int x = 0;
for(double n : numList)
{
x += (int)n * 2;
}
```

\```language
code here
\```

But anyway, taking this step by step:
Go through each number, multiply it by 2, and add it all together, then you have x

Answer 4

and remove anything past the decimal from each*

Answer 5

so 4.17*2=8, rather than 8.34

Answer 6

ok sooo its 20 then

Answer 7

I get 21 actually

Answer 8

But its 8+6+4+2

Answer 9

8 and 2 is 10 then you jsut add the 6 for 16 and then the 4 to get 20

Answer 10

The last one is 3,

Answer 11

But i thought we removed anything past the decimal

Answer 12

And 21 isnt an option

Answer 13

Ah, I was doing it after it multiplied, my bad, lol

Answer 14

So it is 20?

Answer 15

Ok sweet
I got a couple more can you help me with those i feel like im kidna getting it but they are all a bit different

Answer 16

Sure