A model jet is fired up in the air from a 20-foot platform with an initial upward velocity of 68 feet per second. The height of the jet above ground after t seconds is given by the equation -16t^2+68t+20, where h is the height of the jet in feet and t is the time in seconds since it is launched. What is the maximum height the jet reaches, to the nearest foot?
A.
92 feet
B.
20 feet
C.
68 feet
D.
16 feet

Question

umm · Answer

Any ideas/ guesses?

NOpanda14 · Answer

try to limit your choices with the things you know are absolutely not it

Vocaloid · Answer

@Samohtdoowllek if you've learned about derivatives you can just take the derivative and set it equal to 0, then solve for t

otherwise you can try graphing and finding the maximum that way