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Algebra 2 help
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@dude
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There is only 5 questions
Okay for rational functions, you cannot have x values that will make the denominator equal to 0 Any ideas?
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So A?
It cannot be 0, so it is not A
Then D?
Since it's (0, ∞ ) ?
Well it is all values except 0 So it could be \(x|x\in \mathbb R, x\neq 0\)
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