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Mathematics 6 Online
eviant:

Math check

eviant:

1 attachment
eviant:

@Vocaloid

Vocaloid:

hm try again, remember the smallest side is across from smallest angle, and the list should go from smallest to biggest angle

eviant:

@Vocaloid the last one?

Vocaloid:

<K is the smallest angle therefore, the side across from <K, JL, is the smallest

eviant:

so, the 2nd one?

eviant:

@Vocaloid

Vocaloid:

yes

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